What is the integral from 0 to 2 of \sqrt[3]{x^2} ?

The integral from 0 to 2 of \sqrt[3]{x^2} is (6*2^{2/3})/5

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integral from 0 to 2 of \sqrt[3]{x^2}

\frac{6 \cdot 2 ^{\frac{2}{3}}}{5}

Decimal Notation

1.90488 \dots

Solution steps

assuming

x \geq 0

= \int_{0}^{2} x^{\frac{2}{3}} d x

Apply the Power Rule

: [\frac{3}{5} x^{\frac{5}{3}}]_{0}^{2}

= [\frac{3}{5} x^{\frac{5}{3}}]_{0}^{2}

Compute the boundaries:

\frac{6 \cdot 2 ^{\frac{2}{3}}}{5}

= \frac{6 \cdot 2 ^{\frac{2}{3}}}{5}

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What is the integral from 0 to 2 of \sqrt[3]{x^2} ?
The integral from 0 to 2 of \sqrt[3]{x^2} is (6*2^{2/3})/5