What is the integral from 0.8 to 1 of x ?

The integral from 0.8 to 1 of x is 0.18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0.8 to 1 of x

\int_{0.8}^{1} x d x

0.18

Solution steps

\int_{0.8}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0.8}^{1}

= [\frac{x ^{2}}{2}]_{0.8}^{1}

Simplify

= [0.5 x^{2}]_{0.8}^{1}

Compute the boundaries:

0.18

= 0.18

\int_{2}^{\infty} in (2 x - 3) d x

\int_{- \infty}^{0} e^{- ∣ 4 x ∣} d x

\int_{- 1}^{2} (4 x + 2) d x

\int_{- 2}^{2} \frac{x ^{2}}{1 + x ^{3}} d x

\int_{0}^{π} 1 + cos (x) d x

What is the integral from 0.8 to 1 of x ?
The integral from 0.8 to 1 of x is 0.18