What is the integral from 3 to 10 of 1/(sqrt(x-10)) ?

The integral from 3 to 10 of 1/(sqrt(x-10)) is -2sqrt(7)i

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integral from 3 to 10 of 1/(sqrt(x-10))

\int_{3}^{10} \frac{1}{x - 10} d x

- 27 i

Solution steps

\int_{3}^{10} \frac{1}{x - 10} d x

Apply u-substitution

: \int_{7 i}^{0} 2 d u

= \int_{7 i}^{0} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{7 i}^{0}

Compute the boundaries:

- 27 i

= - 27 i

\int_{1}^{l n (2)} x \cdot e^{4 x} d x

\int_{0}^{r} (b r + c) 2 π r d r

\int_{1}^{3} \frac{x}{5 - 2 x + x ^{2}} d x

\int_{0}^{π} tan (2 x) d x

\int_{0}^{1} (x^{2} - x) e^{- x} d x

What is the integral from 3 to 10 of 1/(sqrt(x-10)) ?
The integral from 3 to 10 of 1/(sqrt(x-10)) is -2sqrt(7)i