What is the integral from-3 to infinity of e^{-2x} ?

The integral from-3 to infinity of e^{-2x} is (e^6)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to infinity of e^{-2x}

\int_{- 3}^{\infty} e^{- 2 x} d x

\frac{e ^{6}}{2}

Decimal Notation

201.71439 \dots

Solution steps

\int_{- 3}^{\infty} e^{- 2 x} d x

Compute the indefinite integral:

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x} + C

Compute the boundaries:

\int_{- 3}^{\infty} e^{- 2 x} d x = 0 - (- \frac{e ^{6}}{2})

= 0 - (- \frac{e ^{6}}{2})

Simplify

= \frac{e ^{6}}{2}

\int_{0}^{5} \frac{x ^{2}}{( 5 + 2 x ) ^{2}} d x

\int_{e}^{e^{10}} \frac{1}{x ln ( x )} d x

\int_{0}^{2} y 2 y - y^{2} d y

\int_{1}^{2} x^{2} (x - 2)^{10} d x

What is the integral from-3 to infinity of e^{-2x} ?
The integral from-3 to infinity of e^{-2x} is (e^6)/2