What is the integral from 0 to pi/2 of 3(sin(x))^2 ?

The integral from 0 to pi/2 of 3(sin(x))^2 is (3pi)/4

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integral from 0 to pi/2 of 3(sin(x))^2

\int_{0}^{\frac{π}{2}} 3 (sin (x))^{2} d x

\frac{3 π}{4}

Decimal Notation

2.35619 \dots

Solution steps

\int_{0}^{\frac{π}{2}} 3 (sin (x))^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{\frac{π}{2}} (sin (x))^{2} d x

Simplify

= 3 \cdot \int_{0}^{\frac{π}{2}} sin^{2} (x) d x

Rewrite using trig identities

= 3 \cdot \int_{0}^{\frac{π}{2}} \frac{1 - cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{2} \cdot \int_{0}^{\frac{π}{2}} 1 - cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 3 \cdot \frac{1}{2} (\int_{0}^{\frac{π}{2}} 1 d x - \int_{0}^{\frac{π}{2}} cos (2 x) d x)

\int_{0}^{\frac{π}{2}} 1 d x = \frac{π}{2}

\int_{0}^{\frac{π}{2}} cos (2 x) d x = 0

= 3 \cdot \frac{1}{2} (\frac{π}{2} - 0)

Simplify

3 \cdot \frac{1}{2} (\frac{π}{2} - 0) : \frac{3 π}{4}

= \frac{3 π}{4}

\int_{1}^{e} \frac{1}{x} d x

\int_{0}^{\frac{π}{2}} \frac{x}{x ^{2} - 1} d x

\int_{0}^{\frac{1}{11}} x ln (11 x) d x

\int_{- 3}^{- 2} 2 x d x

\int_{0}^{2} (3 - x) (1 - x^{2}) d x

What is the integral from 0 to pi/2 of 3(sin(x))^2 ?
The integral from 0 to pi/2 of 3(sin(x))^2 is (3pi)/4