What is the integral from 3 to 4 of (e^{ln(x)})/x ?

The integral from 3 to 4 of (e^{ln(x)})/x is 1

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integral from 3 to 4 of (e^{ln(x)})/x

\int_{3}^{4} \frac{e ^{l n (x)}}{x} d x

1

Solution steps

\int_{3}^{4} \frac{e ^{l n (x)}}{x} d x

\frac{e ^{l n (x)}}{x} = 1

= \int_{3}^{4} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{3}^{4}

Simplify

= [x]_{3}^{4}

Compute the boundaries:

1

= 1

\int_{- 1}^{4} \frac{2 x ^{3}}{x ^{2} - 4} d x

\int_{2}^{4} 2 x^{3} + 2 x d x

\int_{1}^{3} x^{2} + x^{4} d x

\int_{- 1}^{0} - (x + 1)^{2} d x

What is the integral from 3 to 4 of (e^{ln(x)})/x ?
The integral from 3 to 4 of (e^{ln(x)})/x is 1