What is the limit as x approaches 4 of 1/((x-4)^3) ?

The limit as x approaches 4 of 1/((x-4)^3) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 4 of 1/((x-4)^3)

x \to 4 lim (\frac{1}{( x - 4 ) ^{3}})

diverges

Solution steps

x \to 4 lim (\frac{1}{( x - 4 ) ^{3}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (\frac{1}{( x - 4 ) ^{3}}) = \infty

x \to 4 - lim (\frac{1}{( x - 4 ) ^{3}}) = - \infty

= diverges

\int 2 x sec (x) tan (x) d x

\frac{d}{d x} (4 sin^{2} (x) + 9 cos^{2} (x))

\frac{\partial}{\partial x} (z^{2} x y)

\frac{d}{d t} (x^{2} + 3)

(cos (\frac{1}{x}) - \frac{1}{x ^{2}}), \frac{1}{3}

What is the limit as x approaches 4 of 1/((x-4)^3) ?
The limit as x approaches 4 of 1/((x-4)^3) is diverges