What is the integral from 0 to 2 of (7x^2-3x+2) ?

The integral from 0 to 2 of (7x^2-3x+2) is 50/3

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integral from 0 to 2 of (7x^2-3x+2)

\int_{0}^{2} (7 x^{2} - 3 x + 2) d x

\frac{50}{3}

Decimal Notation

16.66666 \dots

Solution steps

\int_{0}^{2} 7 x^{2} - 3 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 7 x^{2} d x - \int_{0}^{2} 3 x d x + \int_{0}^{2} 2 d x

\int_{0}^{2} 7 x^{2} d x = \frac{56}{3}

\int_{0}^{2} 3 x d x = 6

\int_{0}^{2} 2 d x = 4

= \frac{56}{3} - 6 + 4

Simplify

\frac{56}{3} - 6 + 4 : \frac{50}{3}

= \frac{50}{3}

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What is the integral from 0 to 2 of (7x^2-3x+2) ?
The integral from 0 to 2 of (7x^2-3x+2) is 50/3