What is the integral from 0 to 32 of 1/(\sqrt[5]{x)} ?

The integral from 0 to 32 of 1/(\sqrt[5]{x)} is 20

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integral from 0 to 32 of 1/(\sqrt[5]{x)}

20

Solution steps

Apply the Power Rule

: [\frac{5}{4} x^{\frac{4}{5}}]_{0}^{32}

= [\frac{5}{4} x^{\frac{4}{5}}]_{0}^{32}

Compute the boundaries:

20

= 20

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What is the integral from 0 to 32 of 1/(\sqrt[5]{x)} ?
The integral from 0 to 32 of 1/(\sqrt[5]{x)} is 20