What is the integral from 0 to 1 of 3x^2sqrt(x^3-5) ?

The integral from 0 to 1 of 3x^2sqrt(x^3-5) is -(16i)/3-Does not exist

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integral from 0 to 1 of 3x^2sqrt(x^3-5)

\int_{0}^{1} 3 x^{2} x^{3} - 5 d x

- \frac{16 i}{3} - Does not exist

Solution steps

\int_{0}^{1} 3 x^{2} x^{3} - 5 d x

Compute the indefinite integral:

\int 3 x^{2} x^{3} - 5 d x = \frac{2}{3} (x^{3} - 5)^{\frac{3}{2}} + C

Compute the boundaries:

\int_{0}^{1} 3 x^{2} x^{3} - 5 d x = - \frac{16 i}{3} -

Does not exist

= - \frac{16 i}{3} - Does not exist

\int_{1}^{5} \frac{x - 1}{x ^{2} ( x + 1 )} d x

\int_{0}^{2} 5 x^{2} - 11 x d x

\int_{1}^{e} (22 + ln (x))^{2} d x

\int_{0}^{1000} e^{4 z} - 5 d z

\int_{0}^{4} \frac{1}{5} e^{- \frac{x}{5}} d x

What is the integral from 0 to 1 of 3x^2sqrt(x^3-5) ?
The integral from 0 to 1 of 3x^2sqrt(x^3-5) is -(16i)/3-Does not exist