What is the integral from-2 to 0 of x^4-2x^2 ?

The integral from-2 to 0 of x^4-2x^2 is 16/15

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integral from-2 to 0 of x^4-2x^2

\int_{- 2}^{0} x^{4} - 2 x^{2} d x

\frac{16}{15}

Decimal

1.06666 \dots

Solution steps

\int_{- 2}^{0} x^{4} - 2 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} x^{4} d x - \int_{- 2}^{0} 2 x^{2} d x

\int_{- 2}^{0} x^{4} d x = \frac{32}{5}

\int_{- 2}^{0} 2 x^{2} d x = \frac{16}{3}

= \frac{32}{5} - \frac{16}{3}

Simplify

\frac{32}{5} - \frac{16}{3} : \frac{16}{15}

= \frac{16}{15}

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What is the integral from-2 to 0 of x^4-2x^2 ?
The integral from-2 to 0 of x^4-2x^2 is 16/15