What is the integral from-5 to 5 of 3x^2-6x-9 ?

The integral from-5 to 5 of 3x^2-6x-9 is 160

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integral from-5 to 5 of 3x^2-6x-9

\int_{- 5}^{5} 3 x^{2} - 6 x - 9 d x

160

Solution steps

\int_{- 5}^{5} 3 x^{2} - 6 x - 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{5} 3 x^{2} d x - \int_{- 5}^{5} 6 x d x - \int_{- 5}^{5} 9 d x

\int_{- 5}^{5} 3 x^{2} d x = 250

\int_{- 5}^{5} 6 x d x = 0

\int_{- 5}^{5} 9 d x = 90

= 250 - 0 - 90

Simplify

= 160

\int_{0}^{1} \frac{13}{4} + \frac{9}{4} x d x

\int_{0}^{1} 1 - r^{2} r d r

\int_{1}^{2} 4 x^{3} - 3 x^{2} + 4 x + 2 d x

\int_{3}^{x} (t^{2} + 1) d t

\int_{0}^{1} k x^{2} + x d x

What is the integral from-5 to 5 of 3x^2-6x-9 ?
The integral from-5 to 5 of 3x^2-6x-9 is 160