What is (\partial)/(\partial x)(2x+cos(y^2)) ?

The answer to (\partial)/(\partial x)(2x+cos(y^2)) is 2

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(\partial)/(\partial x)(2x+cos(y^2))

\frac{\partial}{\partial x} (2 x + cos (y^{2}))

2

Solution steps

\frac{\partial}{\partial x} (2 x + cos (y^{2}))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (cos (y^{2}))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (cos (y^{2})) = 0

= 2 + 0

Simplify

= 2

\frac{x - 3}{9 x - 2}

(3 + 2 x^{- 1} y + 2 x^{- 1} y^{2}) d x + (1 + 2 y) d y = 0

\frac{6 x}{x + 8}, at x = 1

\int (5 sec^{2} (x)) d x

x \to 6 - lim (c x^{2} + 5 x)

What is (\partial)/(\partial x)(2x+cos(y^2)) ?
The answer to (\partial)/(\partial x)(2x+cos(y^2)) is 2