What is the integral from-2 to 2 of (10x^4-x-12) ?

The integral from-2 to 2 of (10x^4-x-12) is 80

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 2 of (10x^4-x-12)

\int_{- 2}^{2} (10 x^{4} - x - 12) d x

80

Solution steps

\int_{- 2}^{2} 10 x^{4} - x - 12 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 10 x^{4} d x - \int_{- 2}^{2} x d x - \int_{- 2}^{2} 12 d x

\int_{- 2}^{2} 10 x^{4} d x = 128

\int_{- 2}^{2} x d x = 0

\int_{- 2}^{2} 12 d x = 48

= 128 - 0 - 48

Simplify

= 80

\int_{0}^{3} 2 x^{4} d x

\int_{- 4}^{4} (x - 2) d x

\int_{2}^{3} x^{2} + 3 d x

\int_{0}^{\frac{π}{2}} - x cos (x) + x d x

\int_{x - 2}^{x^{2}} t - 1 d t

What is the integral from-2 to 2 of (10x^4-x-12) ?
The integral from-2 to 2 of (10x^4-x-12) is 80