What is the limit as x approaches-9+of sqrt(8x+72) ?

The limit as x approaches-9+of sqrt(8x+72) is 0

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limit as x approaches-9+of sqrt(8x+72)

x \to - 9 + lim (8 x + 72)

0

Solution steps

x \to - 9 + lim (8 x + 72)

Plug in the value

x = - 9

= 8 (- 9) + 72

Simplify

= 0

f (x) = sin^{4} (x)

4 + x

\int \frac{1}{( x ^{2} - x - 2 ) ( x - 2 )} d x

y^{^{'}} = 2 y - y^{2}

\int 2 p x d x

What is the limit as x approaches-9+of sqrt(8x+72) ?
The limit as x approaches-9+of sqrt(8x+72) is 0