What is the integral from-1 to 1 of 2tsqrt(1+36t^2) ?

The integral from-1 to 1 of 2tsqrt(1+36t^2) is 0

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integral from-1 to 1 of 2tsqrt(1+36t^2)

\int_{- 1}^{1} 2 t 1 + 36 t^{2} d t

0

Solution steps

\int_{- 1}^{1} 2 t 1 + 36 t^{2} d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

2 t 1 + 36 t^{2} :

Odd

= 0

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What is the integral from-1 to 1 of 2tsqrt(1+36t^2) ?
The integral from-1 to 1 of 2tsqrt(1+36t^2) is 0