What is the integral from-pi to pi of sin(2x)cos(x) ?

The integral from-pi to pi of sin(2x)cos(x) is 0

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integral from-pi to pi of sin(2x)cos(x)

\int_{- π}^{π} sin (2 x) cos (x) d x

0

Solution steps

\int_{- π}^{π} sin (2 x) cos (x) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin (2 x) cos (x) :

Odd

= 0

\int_{1}^{2} [\frac{ln ( x )}{x ^{2}}] d x

\int_{0}^{t} e^{u} u^{2} (t - u)^{2} d u

\int_{0}^{4} e^{y^{2}} (2 - \frac{y}{2}) d y

\int_{0}^{1} x e^{6 x^{2}} d x

\int_{x}^{3 x} \frac{1}{t ^{4} + 1} d t

What is the integral from-pi to pi of sin(2x)cos(x) ?
The integral from-pi to pi of sin(2x)cos(x) is 0