What is the integral from 0 to x of (2-0.2t) ?

The integral from 0 to x of (2-0.2t) is 2x-0.1x^2

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integral from 0 to x of (2-0.2t)

\int_{0}^{x} (2 - 0.2 t) d t

2 x - 0.1 x^{2}

Solution steps

\int_{0}^{x} 2 - 0.2 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{x} 2 d t - \int_{0}^{x} 0.2 t d t

\int_{0}^{x} 2 d t = 2 x

\int_{0}^{x} 0.2 t d t = 0.1 x^{2}

= 2 x - 0.1 x^{2}

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What is the integral from 0 to x of (2-0.2t) ?
The integral from 0 to x of (2-0.2t) is 2x-0.1x^2