What is the integral from 1 to 2 of 1/(y^2) ?

The integral from 1 to 2 of 1/(y^2) is 1/2

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integral from 1 to 2 of 1/(y^2)

\int_{1}^{2} \frac{1}{y ^{2}} d y

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{1}^{2} \frac{1}{y ^{2}} d y

Apply the Power Rule

: [- \frac{1}{y}]_{1}^{2}

= [- \frac{1}{y}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

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\int_{2}^{4} \frac{x + 1}{x ^{2} - x} d x

\int_{0}^{x} \frac{x ^{4}}{1 - x ^{4}} d x

What is the integral from 1 to 2 of 1/(y^2) ?
The integral from 1 to 2 of 1/(y^2) is 1/2