What is the derivative of 1/10 (x-60^2+100) ?

The derivative of 1/10 (x-60^2+100) is 1/5 (x-60)

What is the first derivative of 1/10 (x-60^2+100) ?

The first derivative of 1/10 (x-60^2+100) is 1/5 (x-60)

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\frac{d}{d x} (\frac{1}{10} (x - 60)^{2} + 100)

\frac{1}{5} (x - 60)

Solution steps

\frac{d}{d x} (\frac{1}{10} (x - 60)^{2} + 100)

Simplify

\frac{1}{10} (x - 60)^{2} + 100 : \frac{( x - 60 ) ^{2}}{10} + 100

= \frac{d}{d x} (\frac{( x - 60 ) ^{2}}{10} + 100)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{( x - 60 ) ^{2}}{10}) + \frac{d}{d x} (100)

\frac{d}{d x} (\frac{( x - 60 ) ^{2}}{10}) = \frac{1}{5} (x - 60)

\frac{d}{d x} (100) = 0

= \frac{1}{5} (x - 60) + 0

Simplify

= \frac{1}{5} (x - 60)

- 7 x^{2}

sin^{2} (x)

\int \frac{1}{sec ^{2} ( θ )} d θ

\frac{d ^{2}}{d x ^{2}} (ln (1 - x))

What is the derivative of 1/10 (x-60^2+100) ?
The derivative of 1/10 (x-60^2+100) is 1/5 (x-60)
What is the first derivative of 1/10 (x-60^2+100) ?
The first derivative of 1/10 (x-60^2+100) is 1/5 (x-60)