What is the integral from-2 to 2 of (x+4)^2 ?

The integral from-2 to 2 of (x+4)^2 is 208/3

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integral from-2 to 2 of (x+4)^2

\int_{- 2}^{2} (x + 4)^{2} d x

\frac{208}{3}

Decimal

69.33333 \dots

Solution steps

\int_{- 2}^{2} (x + 4)^{2} d x

Expand

(x + 4)^{2} : x^{2} + 8 x + 16

= \int_{- 2}^{2} x^{2} + 8 x + 16 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} x^{2} d x + \int_{- 2}^{2} 8 x d x + \int_{- 2}^{2} 16 d x

\int_{- 2}^{2} x^{2} d x = \frac{16}{3}

\int_{- 2}^{2} 8 x d x = 0

\int_{- 2}^{2} 16 d x = 64

= \frac{16}{3} + 0 + 64

Simplify

\frac{16}{3} + 0 + 64 : \frac{208}{3}

= \frac{208}{3}

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What is the integral from-2 to 2 of (x+4)^2 ?
The integral from-2 to 2 of (x+4)^2 is 208/3