What is the integral from-3 to 3 of kx^2 ?

The integral from-3 to 3 of kx^2 is k*18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 3 of kx^2

\int_{- 3}^{3} k x^{2} d x

k \cdot 18

Solution steps

\int_{- 3}^{3} k x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{- 3}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 3}^{3}

= k [\frac{x ^{3}}{3}]_{- 3}^{3}

Compute the boundaries:

18

= k \cdot 18

\int_{0}^{20} 2 sin (3 x) d x

\int_{- 1}^{0} \frac{1}{4 x ^{2} + 8 x + 8} d x

\int_{- 1}^{2} 2 x + 4 - 2 x^{2} d x

\int_{- π}^{0} - x^{2} - π x d x

\int_{0}^{t} \frac{9}{1 - x ^{2}} d x

What is the integral from-3 to 3 of kx^2 ?
The integral from-3 to 3 of kx^2 is k*18