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Popular >

integral from-4 to 0 of (x+1)

Solution

\int_{- 4}^{0} (x + 1) d x

Solution

- 4

Solution steps

\int_{- 4}^{0} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 4}^{0} x d x + \int_{- 4}^{0} 1 d x

\int_{- 4}^{0} x d x = - 8

\int_{- 4}^{0} 1 d x = 4

= - 8 + 4

Simplify

= - 4

Popular Examples

integral from-infinity to-2 of 1/(1-x)

\int_{- \infty}^{- 2} \frac{1}{1 - x} d x

integral from 1 to 7 of e^{x^{-3}}

\int_{1}^{7} e^{x^{- 3}} d x

integral from 2 to 3 of cos^5(y)

\int_{2}^{3} cos^{5} (y) d y

integral from 0 to 1000 of e^{4x}-5

\int_{0}^{1000} e^{4 x} - 5 d x

integral from 0 to e of 1/(2x+e)

\int_{0}^{e} \frac{1}{2 x + e} d x

Frequently Asked Questions (FAQ)

What is the integral from-4 to 0 of (x+1) ?
The integral from-4 to 0 of (x+1) is -4