What is the integral of x5^{-x^2} ?

The integral of x5^{-x^2} is -1/(2ln(5))*5^{-x^2}+C

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integral of x5^{-x^2}

\int x 5^{- x^{2}} d x

- \frac{1}{2 ln ( 5 )} \cdot 5^{- x^{2}} + C

Solution steps

\int x \cdot 5^{- x^{2}} d x

Apply u-substitution

: \int - \frac{1}{2 ln ( 5 )} d u

= \int - \frac{1}{2 ln ( 5 )} d u

Integral of a constant:

\int a d x = a x

= (- \frac{1}{2 ln ( 5 )}) u

Substitute back

u = 5^{- x^{2}}

= (- \frac{1}{2 ln ( 5 )}) \cdot 5^{- x^{2}}

Simplify

= - \frac{1}{2 ln ( 5 )} \cdot 5^{- x^{2}}

Add a constant to the solution

= - \frac{1}{2 ln ( 5 )} \cdot 5^{- x^{2}} + C

sec (x)

\frac{1}{( s - 2 ) ( s + 1 )}

(6, - 2), (12, 1)

x \to 2 lim (x^{2} + 3 x)

\frac{d}{d x} (2 + 3 cos (2 x))

What is the integral of x5^{-x^2} ?
The integral of x5^{-x^2} is -1/(2ln(5))*5^{-x^2}+C