What is the integral from 1 to 2 of 8/3 x^3y ?

The integral from 1 to 2 of 8/3 x^3y is 4x^3

Popular >

integral from 1 to 2 of 8/3 x^3y

\int_{1}^{2} \frac{8}{3} x^{3} y d y

4 x^{3}

Solution steps

\int_{1}^{2} \frac{8}{3} x^{3} y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{8}{3} x^{3} \cdot \int_{1}^{2} y d y

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{8 x ^{3}}{3} \cdot \int_{1}^{2} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{1}^{2}

= \frac{8 x ^{3}}{3} [\frac{y ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= \frac{8 x ^{3}}{3} \cdot \frac{3}{2}

Simplify

= 4 x^{3}

\int_{0}^{1} \frac{x}{x ^{2} - 4} d x

\int_{\frac{π}{2}}^{x^{2}} sin^{2} (u) d u

\int_{0}^{π} 10 x cos (x) d x

\int_{0}^{1} \frac{1}{3 x ^{2} - 6 x + 6} d x

\int_{1}^{2} \frac{2}{( 2 x - 5 ) ^{3}} d x

What is the integral from 1 to 2 of 8/3 x^3y ?
The integral from 1 to 2 of 8/3 x^3y is 4x^3