What is the integral from 0 to 1 of-sqrt(x) ?

The integral from 0 to 1 of-sqrt(x) is -2/3

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integral from 0 to 1 of-sqrt(x)

\int_{0}^{1} - x d x

- \frac{2}{3}

Decimal Notation

- 0.66666 \dots

Solution steps

\int_{0}^{1} - x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

= - [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= - \frac{2}{3}

\int_{- 4}^{2} (8 - 2 x - x^{2}) d x

\int_{0}^{1} (x^{2} + 2) e^{- 2 x} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos (t) d t

\int_{- 2}^{2} x + 4 d x

\int_{- \infty}^{0} e^{- ∣ 3 x ∣} d x

What is the integral from 0 to 1 of-sqrt(x) ?
The integral from 0 to 1 of-sqrt(x) is -2/3