What is the integral from-1 to 2 of (x+1)^4 ?

The integral from-1 to 2 of (x+1)^4 is 243/5

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integral from-1 to 2 of (x+1)^4

\int_{- 1}^{2} (x + 1)^{4} d x

\frac{243}{5}

Decimal Notation

48.6

Solution steps

\int_{- 1}^{2} (x + 1)^{4} d x

Apply u-substitution

: \int_{0}^{3} u^{4} d u

= \int_{0}^{3} u^{4} d u

Apply the Power Rule

: [\frac{u ^{5}}{5}]_{0}^{3}

= [\frac{u ^{5}}{5}]_{0}^{3}

Compute the boundaries:

\frac{243}{5}

= \frac{243}{5}

\int_{1}^{x} (2 - t) d t

\int_{1}^{2} x (1 + x^{2})^{3} d x

\int_{2}^{\infty} \frac{1}{5 x - 1} d x

\int_{- 2}^{5} x^{2} - 2 x - 3 d x

\int_{- 1}^{3} u (1 - 2 u) d u

What is the integral from-1 to 2 of (x+1)^4 ?
The integral from-1 to 2 of (x+1)^4 is 243/5