What is the integral from 0.75 to 0.9 of 3x^2 ?

The integral from 0.75 to 0.9 of 3x^2 is 0.307125

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integral from 0.75 to 0.9 of 3x^2

\int_{0.75}^{0.9} 3 x^{2} d x

0.307125

Solution steps

\int_{0.75}^{0.9} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0.75}^{0.9} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0.75}^{0.9}

= 3 [\frac{x ^{3}}{3}]_{0.75}^{0.9}

Simplify

= 3 [0.33333 \dots x^{3}]_{0.75}^{0.9}

Compute the boundaries:

0.102375

= 3 \cdot 0.102375

Simplify

= 0.307125

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What is the integral from 0.75 to 0.9 of 3x^2 ?
The integral from 0.75 to 0.9 of 3x^2 is 0.307125