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Popular >

integral from 0 to 4 of |3x-9|

Solution

\int_{0}^{4} ∣ 3 x - 9 ∣ d x

Solution

15

Solution steps

\int_{0}^{4} ∣ 3 x - 9 ∣ d x

Eliminate Absolutes

= \int_{0}^{3} - 3 x + 9 d x + \int_{3}^{4} 3 x - 9 d x

\int_{0}^{3} - 3 x + 9 d x = \frac{27}{2}

\int_{3}^{4} 3 x - 9 d x = \frac{3}{2}

= \frac{27}{2} + \frac{3}{2}

Simplify

\frac{27}{2} + \frac{3}{2} : 15

= 15

Popular Examples

integral from 0 to infinity of e^{-t}t^5

\int_{0}^{\infty} e^{- t} t^{5} d t

integral from 11 to infinity of 1/(x^3)

\int_{11}^{\infty} \frac{1}{x ^{3}} d x

integral from 0 to 3 of 1/((3-x)^2)

\int_{0}^{3} \frac{1}{( 3 - x ) ^{2}} d x

integral from-1 to 3 of (-x^3+3x^2-5)

\int_{- 1}^{3} (- x^{3} + 3 x^{2} - 5) d x

integral from 0 to 2 of c(4x-2x^2)

\int_{0}^{2} c (4 x - 2 x^{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of |3x-9| ?
The integral from 0 to 4 of |3x-9| is 15