What is the integral from 0 to 6 of x/(18) ?

The integral from 0 to 6 of x/(18) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 6 of x/(18)

\int_{0}^{6} \frac{x}{18} d x

1

Solution steps

\int_{0}^{6} \frac{x}{18} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{18} \cdot \int_{0}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{6}

= \frac{1}{18} [\frac{x ^{2}}{2}]_{0}^{6}

Compute the boundaries:

18

= \frac{1}{18} \cdot 18

Simplify

= 1

\int_{- 0.5}^{0.5} 1 - x^{2} d x

\int_{1}^{3 x} ln (x) d x

\int_{- 1}^{4} x + 4 - x^{2} + 2 x d x

\int_{5}^{10} \frac{1}{36 - 9 x ^{2}} d x

\int_{- 2}^{2} (x + 2)^{3} d x

What is the integral from 0 to 6 of x/(18) ?
The integral from 0 to 6 of x/(18) is 1