What is the integral from 2 to 2 of cos(e^t+ln(t)) ?

The integral from 2 to 2 of cos(e^t+ln(t)) is 0

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integral from 2 to 2 of cos(e^t+ln(t))

\int_{2}^{2} cos (e^{t} + ln (t)) d t

0

Solution steps

\int_{2}^{2} cos (e^{t} + ln (t)) d t

\int_{a}^{a} f (x) d x = 0, a \neq = \infty

= 0

\int_{0}^{1} \frac{x}{x ^{4} + 1} d x

\int_{2}^{5} (3 - ∣ x - 4 ∣) d x

\int_{1}^{2} x - 1 - (x - 1)^{4} d x

\int_{1}^{2} x (\frac{3}{7} x^{2}) d x

\int_{0}^{1} x ln (1 + \frac{1}{x}) d x

What is the integral from 2 to 2 of cos(e^t+ln(t)) ?
The integral from 2 to 2 of cos(e^t+ln(t)) is 0