What is the integral from-2pi to-pi of sin(x) ?

The integral from-2pi to-pi of sin(x) is 2

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integral from-2pi to-pi of sin(x)

\int_{- 2 π}^{- π} sin (x) d x

2

Solution steps

\int_{- 2 π}^{- π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- 2 π}^{- π}

Compute the boundaries:

2

= 2

\int_{0}^{2} (2 x - cos (4 x)) d x

\int_{1}^{3} 27 - x^{3} d x

\int_{0}^{1} 4 x y x^{2} + y^{2} d y

\int_{- 3}^{- 1} y^{3} 49 y^{2} - 4 d y

\int_{0}^{0.5} x^{4} e^{- x^{2}} d x

What is the integral from-2pi to-pi of sin(x) ?
The integral from-2pi to-pi of sin(x) is 2