What is the derivative of (t+7)^2 ?

The derivative of (t+7)^2 is 2(t+7)

What is the first derivative of (t+7)^2 ?

The first derivative of (t+7)^2 is 2(t+7)

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derivative of

(t + 7)^{2}

2 (t + 7)

Solution steps

\frac{d}{d t} ((t + 7)^{2})

Apply the chain rule:

2 (t + 7) \frac{d}{d t} (t + 7)

= 2 (t + 7) \frac{d}{d t} (t + 7)

\frac{d}{d t} (t + 7) = 1

= 2 (t + 7) \cdot 1

Simplify

= 2 (t + 7)

x \to \infty lim (x + 0)

e^{x + 1}

\frac{d}{d x} (arctan (\frac{1 + x}{1 - x}))

\frac{d}{d t} (t e^{- 1})

(cos (x) - x sin (x))^{^{'}}

What is the derivative of (t+7)^2 ?
The derivative of (t+7)^2 is 2(t+7)
What is the first derivative of (t+7)^2 ?
The first derivative of (t+7)^2 is 2(t+7)