What is the integral from-pi/4 to pi/4 of sec^2(t) ?

The integral from-pi/4 to pi/4 of sec^2(t) is 2

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integral from-pi/4 to pi/4 of sec^2(t)

\int_{- \frac{π}{4}}^{\frac{π}{4}} sec^{2} (t) d t

2

Solution steps

\int_{- \frac{π}{4}}^{\frac{π}{4}} sec^{2} (t) d t

Use the common integral:

\int sec^{2} (t) d t = tan (t)

= [tan (t)]_{- \frac{π}{4}}^{\frac{π}{4}}

Compute the boundaries:

2

= 2

\int_{- 1}^{1} x y^{2} d y

\int_{0}^{1} sin (π) t d t

\int_{5}^{6} x (x - 5)^{2} d x

\int_{0}^{1} x 4^{x} d x

\int_{0}^{1} (x - x^{3})^{2} d x

What is the integral from-pi/4 to pi/4 of sec^2(t) ?
The integral from-pi/4 to pi/4 of sec^2(t) is 2