What is the integral from 0 to infinity of 25e^{-5x} ?

The integral from 0 to infinity of 25e^{-5x} is 5

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integral from 0 to infinity of 25e^{-5x}

\int_{0}^{\infty} 25 e^{- 5 x} d x

5

Solution steps

\int_{0}^{\infty} 25 e^{- 5 x} d x

Compute the indefinite integral:

\int 25 e^{- 5 x} d x = - 5 e^{- 5 x} + C

Compute the boundaries:

\int_{0}^{\infty} 25 e^{- 5 x} d x = 0 - (- 5)

= 0 - (- 5)

Simplify

= 5

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What is the integral from 0 to infinity of 25e^{-5x} ?
The integral from 0 to infinity of 25e^{-5x} is 5