What is the integral from 2 to 5 of (x^2+1/(x^2)) ?

The integral from 2 to 5 of (x^2+1/(x^2)) is 393/10

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integral from 2 to 5 of (x^2+1/(x^2))

\int_{2}^{5} (x^{2} + \frac{1}{x ^{2}}) d x

\frac{393}{10}

Decimal Notation

39.3

Solution steps

\int_{2}^{5} x^{2} + \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} x^{2} d x + \int_{2}^{5} \frac{1}{x ^{2}} d x

\int_{2}^{5} x^{2} d x = 39

\int_{2}^{5} \frac{1}{x ^{2}} d x = \frac{3}{10}

= 39 + \frac{3}{10}

Simplify

39 + \frac{3}{10} : \frac{393}{10}

= \frac{393}{10}

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What is the integral from 2 to 5 of (x^2+1/(x^2)) ?
The integral from 2 to 5 of (x^2+1/(x^2)) is 393/10