What is the integral from 0 to x^2 of t^3 ?

The integral from 0 to x^2 of t^3 is (x^8)/4

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integral from 0 to x^2 of t^3

\int_{0}^{x^{2}} t^{3} d t

\frac{x ^{8}}{4}

Solution steps

\int_{0}^{x^{2}} t^{3} d t

Apply the Power Rule

: [\frac{t ^{4}}{4}]_{0}^{x^{2}}

= [\frac{t ^{4}}{4}]_{0}^{x^{2}}

Compute the boundaries:

\frac{x ^{8}}{4}

= \frac{x ^{8}}{4}

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\int_{0}^{1} \frac{1}{y} + x d x

What is the integral from 0 to x^2 of t^3 ?
The integral from 0 to x^2 of t^3 is (x^8)/4