What is the integral from 1/7 to 5 of 6xln(7x) ?

The integral from 1/7 to 5 of 6xln(7x) is 6(-306/49+25/2 ln(35))

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integral from 1/7 to 5 of 6xln(7x)

\int_{\frac{1}{7}}^{5} 6 x ln (7 x) d x

6 (- \frac{306}{49} + \frac{25}{2} ln (35))

Decimal Notation

229.18171 \dots

Solution steps

\int_{\frac{1}{7}}^{5} 6 x ln (7 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{\frac{1}{7}}^{5} x ln (7 x) d x

Apply Integration By Parts

: [\frac{1}{2} x^{2} ln (7 x) - \int \frac{x}{2} d x]_{\frac{1}{7}}^{5}

= 6 [\frac{1}{2} x^{2} ln (7 x) - \int \frac{x}{2} d x]_{\frac{1}{7}}^{5}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 6 [\frac{1}{2} x^{2} ln (7 x) - \frac{x ^{2}}{4}]_{\frac{1}{7}}^{5}

Compute the boundaries:

- \frac{306}{49} + \frac{25}{2} ln (35)

= 6 (- \frac{306}{49} + \frac{25}{2} ln (35))

\frac{d}{d x} (\frac{8}{x - 3})

x \to \frac{π}{2} lim (x \cdot sec (x))

x y^{^{'}} + 2 y = 0

\int_{0}^{a} r^{2} e^{- \frac{2 r}{a}} d r

\int \frac{2 x ^{2}}{2 x - 3} d x

What is the integral from 1/7 to 5 of 6xln(7x) ?
The integral from 1/7 to 5 of 6xln(7x) is 6(-306/49+25/2 ln(35))