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Popular >

integral from 1 to 4 of 6x^2-4x+1

Solution

\int_{1}^{4} 6 x^{2} - 4 x + 1 d x

Solution

99

Solution steps

\int_{1}^{4} 6 x^{2} - 4 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 6 x^{2} d x - \int_{1}^{4} 4 x d x + \int_{1}^{4} 1 d x

\int_{1}^{4} 6 x^{2} d x = 126

\int_{1}^{4} 4 x d x = 30

\int_{1}^{4} 1 d x = 3

= 126 - 30 + 3

Simplify

= 99

Popular Examples

integral from 0 to 2 of x^2ln(x^2+1)

\int_{0}^{2} x^{2} ln (x^{2} + 1) d x

integral from 0 to 1 of 1/4 (2x+y)

\int_{0}^{1} \frac{1}{4} (2 x + y) d y

integral from 1 to 4 of x^2-2x-1

\int_{1}^{4} x^{2} - 2 x - 1 d x

integral from 1 to 9 of (9-x)^{1/3}

\int_{1}^{9} (9 - x)^{\frac{1}{3}} d x

integral from 1/4 to 1 of arcsin(x)

\int_{\frac{1}{4}}^{1} arcsin (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of 6x^2-4x+1 ?
The integral from 1 to 4 of 6x^2-4x+1 is 99