What is the integral from 1 to 2.8 of ln(x^2) ?

The integral from 1 to 2.8 of ln(x^2) is 2.16586…

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integral from 1 to 2.8 of ln(x^2)

\int_{1}^{2.8} ln (x^{2}) d x

2.16586 \dots

Solution steps

\int_{1}^{2.8} ln (x^{2}) d x

Apply Integration By Parts

: [x ln (x^{2}) - \int 2 d x]_{1}^{2.8}

= [x ln (x^{2}) - \int 2 d x]_{1}^{2.8}

\int 2 d x = 2 x

= [x ln (x^{2}) - 2 x]_{1}^{2.8}

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

= [2 x ln (x) - 2 x]_{1}^{2.8}

Compute the boundaries:

2.16586 \dots

= 2.16586 \dots

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What is the integral from 1 to 2.8 of ln(x^2) ?
The integral from 1 to 2.8 of ln(x^2) is 2.16586…