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Popular >

integral from 0 to 2 of 2x^2+x-1

Solution

\int_{0}^{2} 2 x^{2} + x - 1 d x

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

\int_{0}^{2} 2 x^{2} + x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x^{2} d x + \int_{0}^{2} x d x - \int_{0}^{2} 1 d x

\int_{0}^{2} 2 x^{2} d x = \frac{16}{3}

\int_{0}^{2} x d x = 2

\int_{0}^{2} 1 d x = 2

= \frac{16}{3} + 2 - 2

Simplify

= \frac{16}{3}

Popular Examples

integral from 0 to 2 of sqrt(5x^2+4x+29)

\int_{0}^{2} 5 x^{2} + 4 x + 29 d x

integral from 1 to 5 of sqrt(2t-1)

\int_{1}^{5} 2 t - 1 d t

integral from 0 to 4 of (sqrt(x)(x-1))

\int_{0}^{4} (x (x - 1)) d x

integral from 0 to 4pi of |sin(2x)|

\int_{0}^{4 π} ∣ sin (2 x) ∣ d x

integral from 0 to pi/2 of x(-cos(x)+1)

\int_{0}^{\frac{π}{2}} x (- cos (x) + 1) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of 2x^2+x-1 ?
The integral from 0 to 2 of 2x^2+x-1 is 16/3