What is the integral from-1 to 1 of 2x^3+(3^x)/2 ?

The integral from-1 to 1 of 2x^3+(3^x)/2 is 4/(3ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of 2x^3+(3^x)/2

\int_{- 1}^{1} 2 x^{3} + \frac{3 ^{x}}{2} d x

\frac{4}{3 ln ( 3 )}

Decimal Notation

1.21365 \dots

Solution steps

\int_{- 1}^{1} 2 x^{3} + \frac{3 ^{x}}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 x^{3} d x + \int_{- 1}^{1} \frac{3 ^{x}}{2} d x

\int_{- 1}^{1} 2 x^{3} d x = 0

\int_{- 1}^{1} \frac{3 ^{x}}{2} d x = \frac{4}{3 ln ( 3 )}

= 0 + \frac{4}{3 ln ( 3 )}

Simplify

= \frac{4}{3 ln ( 3 )}

\int_{0}^{1} (9 x + 2)^{30} d x

\int_{0}^{π} (x) d x

\int_{1}^{2} (x - 1)^{4} d x

\int_{\frac{y}{2}}^{y} (4 x + 2) d x

\int_{0}^{1.5} 2 x e^{- x^{2}} d x

What is the integral from-1 to 1 of 2x^3+(3^x)/2 ?
The integral from-1 to 1 of 2x^3+(3^x)/2 is 4/(3ln(3))