What is the derivative of x^3+y^3-3x^2y^2+1 ?

The derivative of x^3+y^3-3x^2y^2+1 is 3x^2-6xy^2

What is the first derivative of x^3+y^3-3x^2y^2+1 ?

The first derivative of x^3+y^3-3x^2y^2+1 is 3x^2-6xy^2

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derivative of

x^{3} + y^{3} - 3 x^{2} y^{2} + 1

3 x^{2} - 6 x y^{2}

Solution steps

\frac{d}{d x} (x^{3} + y^{3} - 3 x^{2} y^{2} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (y^{3}) - \frac{d}{d x} (3 x^{2} y^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (y^{3}) = 0

\frac{d}{d x} (3 x^{2} y^{2}) = 6 y^{2} x

\frac{d}{d x} (1) = 0

= 3 x^{2} + 0 - 6 y^{2} x + 0

Simplify

= 3 x^{2} - 6 x y^{2}

y^{^{''}} + y^{^{'}} - 2 y = 2 t

\int_{0}^{3} x^{2} d x

\int \frac{2 x ^{3} + x ^{2} - x}{x ^{2}} d x

\int (e^{x} + x^{e}) d x

f (x) = - arctan (x)

What is the derivative of x^3+y^3-3x^2y^2+1 ?
The derivative of x^3+y^3-3x^2y^2+1 is 3x^2-6xy^2
What is the first derivative of x^3+y^3-3x^2y^2+1 ?
The first derivative of x^3+y^3-3x^2y^2+1 is 3x^2-6xy^2