What is the integral from-infinity to 4 of 3e^{-3x} ?

The integral from-infinity to 4 of 3e^{-3x} is diverges

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integral from-infinity to 4 of 3e^{-3x}

\int_{- \infty}^{4} 3 e^{- 3 x} d x

diverges

Solution steps

\int_{- \infty}^{4} 3 e^{- 3 x} d x

Compute the indefinite integral:

\int 3 e^{- 3 x} d x = - e^{- 3 x} + C

Compute the boundaries:

\int_{- \infty}^{4} 3 e^{- 3 x} d x =

diverges

= diverges

\int_{- 2}^{2} (2 - 4 - x^{2}) d x

\int_{- 1}^{0} (2 x + 1)^{3} d x

\int_{1}^{2} (\frac{1}{y} + \frac{2}{3}) d y

\int_{0}^{1} (arcsin (t))^{2} d t

\int_{1}^{3} x y^{2} + x^{2} + y + 4

What is the integral from-infinity to 4 of 3e^{-3x} ?
The integral from-infinity to 4 of 3e^{-3x} is diverges