What is the integral from 0 to infinity of 8/(x^2-4) ?

The integral from 0 to infinity of 8/(x^2-4) is diverges

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integral from 0 to infinity of 8/(x^2-4)

\int_{0}^{\infty} \frac{8}{x ^{2} - 4} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{8}{x ^{2} - 4} d x

Adjust integral based on undefined pointsThere is an undefined point within the boundaries at

: 2

= \int_{0}^{2} \frac{8}{x ^{2} - 4} d x + \int_{2}^{\infty} \frac{8}{x ^{2} - 4} d x

\int_{0}^{2} \frac{8}{x ^{2} - 4} d x =

diverges

= diverges

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What is the integral from 0 to infinity of 8/(x^2-4) ?
The integral from 0 to infinity of 8/(x^2-4) is diverges