What is the integral from-1 to 0 of (x^2-4x+7) ?

The integral from-1 to 0 of (x^2-4x+7) is 28/3

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integral from-1 to 0 of (x^2-4x+7)

\int_{- 1}^{0} (x^{2} - 4 x + 7) d x

\frac{28}{3}

Decimal Notation

9.33333 \dots

Solution steps

\int_{- 1}^{0} x^{2} - 4 x + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} x^{2} d x - \int_{- 1}^{0} 4 x d x + \int_{- 1}^{0} 7 d x

\int_{- 1}^{0} x^{2} d x = \frac{1}{3}

\int_{- 1}^{0} 4 x d x = - 2

\int_{- 1}^{0} 7 d x = 7

= \frac{1}{3} - (- 2) + 7

Simplify

\frac{1}{3} - (- 2) + 7 : \frac{28}{3}

= \frac{28}{3}

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What is the integral from-1 to 0 of (x^2-4x+7) ?
The integral from-1 to 0 of (x^2-4x+7) is 28/3