What is the integral from 0 to sqrt(-2 of)[x^3-2x] ?

The integral from 0 to sqrt(-2 of)[x^3-2x] is 3

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integral from 0 to sqrt(-2 of)[x^3-2x]

\int_{0}^{- 2} [x^{3} - 2 x] d x

3

Solution steps

\int_{0}^{- 2} x^{3} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{- 2} x^{3} d x - \int_{0}^{- 2} 2 x d x

\int_{0}^{- 2} x^{3} d x = 1

\int_{0}^{- 2} 2 x d x = - 2

= 1 - (- 2)

Simplify

= 3

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What is the integral from 0 to sqrt(-2 of)[x^3-2x] ?
The integral from 0 to sqrt(-2 of)[x^3-2x] is 3