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Popular >

integral from 1 to 2 of (x^2+4)

Solution

\int_{1}^{2} (x^{2} + 4) d x

Solution

\frac{19}{3}

+1

Decimal

6.33333 \dots

Solution steps

\int_{1}^{2} x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} 4 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 4 d x = 4

= \frac{7}{3} + 4

Simplify

\frac{7}{3} + 4 : \frac{19}{3}

= \frac{19}{3}

Graph

Popular Examples

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\int_{0}^{2 π} 6 x 2 d x

integral from 1 to 2 of ((x^2)/4+1)

\int_{1}^{2} (\frac{x ^{2}}{4} + 1) d x

integral from 0 to 10 of xe^{-x^2}

\int_{0}^{10} x e^{- x^{2}} d x

integral from 3 to 5 of 1/(sqrt(|x-1|))

\int_{3}^{5} \frac{1}{∣ x - 1 ∣} d x

integral from 6 to 10 of 3x^2+1

\int_{6}^{10} 3 x^{2} + 1 d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^2+4) ?
The integral from 1 to 2 of (x^2+4) is 19/3