en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 3 of (x^2+x)

Solution

\int_{- 1}^{3} (x^{2} + x) d x

Solution

\frac{40}{3}

+1

Decimal Notation

13.33333 \dots

Solution steps

\int_{- 1}^{3} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} x^{2} d x + \int_{- 1}^{3} x d x

\int_{- 1}^{3} x^{2} d x = \frac{28}{3}

\int_{- 1}^{3} x d x = 4

= \frac{28}{3} + 4

Simplify

\frac{28}{3} + 4 : \frac{40}{3}

= \frac{40}{3}

Popular Examples

integral from 0 to 0.99 of 1/(1-x)

\int_{0}^{0.99} \frac{1}{1 - x} d x

integral from 2 to infinity of 4/(x^4)

\int_{2}^{\infty} \frac{4}{x ^{4}} d x

integral from 0 to 9 of 300e^{-0.11x}

\int_{0}^{9} 300 e^{- 0.11 x} d x

integral from-1 to 1 of 5t^4

\int_{- 1}^{1} 5 t^{4} d t

integral from 1 to 2 of 2x^3-x^2

\int_{1}^{2} 2 x^{3} - x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 3 of (x^2+x) ?
The integral from-1 to 3 of (x^2+x) is 40/3