What is the integral from-7 to 6 of-2y^3-y^2+36 ?

The integral from-7 to 6 of-2y^3-y^2+36 is 5005/6

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integral from-7 to 6 of-2y^3-y^2+36

\int_{- 7}^{6} - 2 y^{3} - y^{2} + 36 d y

\frac{5005}{6}

Decimal Notation

834.16666 \dots

Solution steps

\int_{- 7}^{6} - 2 y^{3} - y^{2} + 36 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 7}^{6} 2 y^{3} d y - \int_{- 7}^{6} y^{2} d y + \int_{- 7}^{6} 36 d y

\int_{- 7}^{6} 2 y^{3} d y = - \frac{1105}{2}

\int_{- 7}^{6} y^{2} d y = \frac{559}{3}

\int_{- 7}^{6} 36 d y = 468

= - (- \frac{1105}{2}) - \frac{559}{3} + 468

Simplify

- (- \frac{1105}{2}) - \frac{559}{3} + 468 : \frac{5005}{6}

= \frac{5005}{6}

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What is the integral from-7 to 6 of-2y^3-y^2+36 ?
The integral from-7 to 6 of-2y^3-y^2+36 is 5005/6